The coordinates of the foot of the perpendicular drawn from the origin upon a line are (h,k) , show that the equation of the line is `hx+ky=h^(2)+k^(2)(h^(2)+k^(2)ne0)`.

The foot of the perpendicular drawn from the origin to a plane is (2, -3, 4), then the equation of the plane is -

The co-ordinates of the foot of the perpendicular from (0, 0) upon the line x+y=2 are

Find the coordinates of the foot of the perpendicular drawn from the point (2,-5) on the straight line x=y+1.

The coordinates of the foot of the perpendicular from the point (2,3) on the line -y+3x+4=0 are given by

Find the coordinates of the foot of the perpendicular drawn from the point P(1,-2) on the line y = 2x +1. Also, find the image of P in the line.

Find the foot of perpendicular drawn from the point (2, 2) to the line 3x - 4y + 5 = 0

The coordinates of the foot of the perpendicular drawn from the point A(2, 4, -1) on the line (x+5)/(1)=(y+3)/(4)=(z-6)/(-9) are -

Find the locus of the foot of the perpendicular from the origin upon a stright line which always passes through the point (2,3).

If the length of the perpendicular drawn from the point (3,-5) upon the line 12x+ky=9 be 4 unit , find the value of k.

A circle of radius r passes through the origin and intersects the x-axis and y-axis at P and Q respectively. Show that the equation to the locus of the foot of the perpendicular drawn form the origin upon the line segment bar (PQ) is (x^(2)+y^(2))^(3)=4r^(2)x^(2)y^(2) .