Home
Class 11
MATHS
The foci of the ellipse (x^(2))/(25) + (...

The foci of the ellipse `(x^(2))/(25) + (y^(2))/(9) = 1` coincide with the hyperbola. It e = 2 for hyperbola, find the equation of the hyperbola.

Text Solution

Verified by Experts

The correct Answer is:
`3x^(2) - y^(2) = 12`
Promotional Banner

Topper's Solved these Questions

  • HYPERBOLA

    CHHAYA PUBLICATION|Exercise SAMPLE QUESTIONS FOR COMPETITIVE EXAMS|12 Videos

  • HYPERBOLA

    CHHAYA PUBLICATION|Exercise SHORT ANSWER TYPE QUESTIONS|37 Videos

  • DIAGRAMMATIC REPRESENTATION OF DATA

    CHHAYA PUBLICATION|Exercise EXERCISE (Very short Answer Type Question)|7 Videos

  • MATHEMATICAL INDUCTION

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams|20 Videos

Similar Questions

Explore conceptually related problems

The foci of the ellipse x^2/25+y^2/9=1 coincide with a hyperbola. If e=2 for hyperbola, find the equation of hyperbola.

If foci of the ellipse (x^(2))/(16) + (y^(2))/(b^(2)) = 1 coincide with the foci of the hyperbola (x^(2)/(144) - (y^(2))/(81)) = (1)/(25) , then the value of b^(2) is -

Find the foci of the ellipse 25(x+1)^2+9(y+2)^2=225.

The four foci of the hyperbola (x^(2))/(a^(2)) - (y^(2))/(b^(2)) = 1 and its conjugate are joined to form a parallelogram. Find the area of the parallelogram .

If the ellipse x^(2)+2y^(2)=4 and the hyperbola S = 0 have same end points of the latus rectum, then the eccentricity of the hyperbola can be

If the foci of the ellipse (x^2)/(16)+(y^2)/(b^2)=1 and the hyperbola (x^2)/(144)-(y^2)/(81)=1/(25) coincide, then find the value of b^2

let the eccentricity of the hyperbola x^2/a^2-y^2/b^2=1 be reciprocal to that of the ellipse x^2+4y^2=4. if the hyperbola passes through a focus of the ellipse then: (a) the equation of the hyperbola is x^2/3-y^2/2=1 (b) a focus of the hyperbola is (2,0) (c) the eccentricity of the hyperbola is sqrt(5/3) (d) the equation of the hyperbola is x^2-3y^2=3

The ellipse (x^(2))/(25)+(y^(2))/(16)=1 and the hyperbola (x^(2))/(25)-(y^(2))/(16) =1 have in common

If the foci of (x^2)/(a^2)-(y^2)/(b^2)=1 coincide with the foci of (x^2)/(25)+(y^2)/9=1 and the eccentricity of the hyperbola is 2, then

The foci of the hyperbola 4x^2-9y^2=36 is