Home
Class 12
CHEMISTRY
A natural linear polymer of 2-methyl-1, ...

A natural linear polymer of 2-methyl-1, 3-butadiene becomes hard on treatment with sulphur between 373 to 415 K and -S-S- bonds are formed between chains. Write structure of the product ofthis treatment.

Text Solution

Verified by Experts

Vulcanized rubber
Promotional Banner

Topper's Solved these Questions

  • POLYMERS

    CHHAYA PUBLICATION|Exercise MCQ HOTSPOT|55 Videos
  • POLYMERS

    CHHAYA PUBLICATION|Exercise EXERCISE|50 Videos
  • POLYMERS

    CHHAYA PUBLICATION|Exercise ENTRANCE QUESTION BANK|26 Videos
  • P-BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET 7 (ANSWER THE FOLLOWING QUESTIONS) : -|17 Videos
  • PREVIOUS YEAR QUESTION PAPER 2018

    CHHAYA PUBLICATION|Exercise NEET 2018|18 Videos

Similar Questions

Explore conceptually related problems

A natural polymer of 2-methyl-1,3-butadiene when treated with sulphur at 373K to 415 K, it gets hardened . In the reaction , chains of polymers become connected by -S-S- linkages. Write the structure of the substance formed in the reaction

Write down the Arrhenius equation relating the rate constant of a reaction with temp. If K_1 and K_2 be the rate constants of reaction at temperature t_1^@C and t_2^@C respectively, Find out the relation between K_1 , K_2 , t_1 and t_2 . Give that the activation energy (E_a) of the reaction remains unchnaged within the temp. range mentioned. The rate constants of a reaction at 400K and 500K are 0.02 S^-1 and 0.085 S^-1 respectively. Determine the activation energy (E_a) of the reaction.

In Young' s double slit experiment, two monochromatic light of wavelengths 650 nm and 520 nm are used to form an interference pattern . Seprsation between the two slits is 2xx 10^(-3) m and screen is 1.20 m away from the slits. At what minimum distance apart from the central maxima, bright fringes due to both the waves will be overlapped?

Electromagnetic waves propagate through free space or a medium as transverse waves. The electric and magnetic fields are perpendicular to each other as well as perpendicular to the direction of propagation of waves at each point. In the direction of wave propagation, electric field vecE and magnetic field vecB form a right-handed cartesian coordinate system. During the propagation of electromagnetic wave, total energy of electromagnetic wave is distributed equally between electric and magnetic fields. Since in_0 and mu_0 are permittivity and permeability of free space, the velocity of electromagnetic wave, c=(in_0 mu_0)^(-1//2) . Energy density i.e., energy in unit volume due to electric field at any point, u_E=1/2in_0E^2 Similarly, energy density due to magnetic field , u_M=1/(2mu_0)B^2 . If the electromagnetic wave propagates along x-direction, then the equations of electric and magnetic field are respectively. E=E_0sin(omegat-kx) and B=B_0sin(omegat-kx) Here, the frequency and the wavelength of oscillating electric and magnetic fields are f=omega/(2pi) and lambda=(2pi)/k respectively. Thus E_"rms"=E_0/sqrt2 and B_"rms"=B_0/sqrt2 , where E_0/B_0=c . Therefore, average energy density baru_E=1/2in_0E_"rms"^2 and baru_M=1/(2mu_0)B_"rms"^2 . The intensity of the electromagnetic wave at a point, I=cbaru=c(baru_E+baru_B) . To answer the following questions , we assume that in case of propagation of electromagnetic wave through free space, c=3xx10^8 m.s^(-1) and mu_0=4pixx10^(-7) H.m^(-1) Relation between omega and k

Electromagnetic waves propagate through free space or a medium as transverse waves. The electric and magnetic fields are perpendicular to each other as well as perpendicular to the direction of propagation of waves at each point. In the direction of wave propagation, electric field vecE and magnetic field vecB form a right-handed cartesian coordinate system. During the propagation of electromagnetic wave, total energy of electromagnetic wave is distributed equally between electric and magnetic fields. Since in_0 and mu_0 are permittivity and permeability of free space, the velocity of electromagnetic wave, c=(in_0 mu_0)^(-1//2) . Energy density i.e., energy in unit volume due to electric field at any point, u_E=1/2in_0E^2 Similarly, energy density due to magnetic field , u_M=1/(2mu_0)B^2 . If the electromagnetic wave propagates along x-direction, then the equations of electric and magnetic field are respectively. E=E_0sin(omegat-kx) and B=B_0sin(omegat-kx) Here, the frequency and the wavelength of oscillating electric and magnetic fields are f=omega/(2pi) and lambda=(2pi)/k respectively. Thus E_"rms"=E_0/sqrt2 and B_"rms"=B_0/sqrt2 , where E_0/B_0=c . Therefore, average energy density baru_E=1/2in_0E_"rms"^2 and baru_M=1/(2mu_0)B_"rms"^2 . The intensity of the electromagnetic wave at a point, I=cbaru=c(baru_E+baru_B) . To answer the following questions , we assume that in case of propagation of electromagnetic wave through free space, c=3xx10^8 m.s^(-1) and mu_0=4pixx10^(-7) H.m^(-1) If the peak value of electric field at a point in electromagnetic wave is 15 V . m^(-1) , then average electrical energy density (in j . m^(-3) )

CHHAYA PUBLICATION-POLYMERS -SOLVED NCERT EXEMPLAR PROBLEMS
  1. Which of the following polymers have vinylic monomer units

    Text Solution

    |

  2. Vulcanisation makes rubber-

    Text Solution

    |

  3. A natural linear polymer of 2-methyl-1, 3-butadiene becomes hard on tr...

    Text Solution

    |

  4. Identify the type of polymer. -A-A-A-A-A-

    Text Solution

    |

  5. Identify the type of polymer. -A-B-B-A-A-A-B-A-

    Text Solution

    |

  6. Out of chain growth polymerisation and step growth polymerisation, in ...

    Text Solution

    |

  7. Identify the type of polymer in the following figure.

    Text Solution

    |

  8. Identify the polymer given below:

    Text Solution

    |

  9. Why are rubbers called elastomers?

    Text Solution

    |

  10. Can enzyme be called a polymer?

    Text Solution

    |

  11. Can nucleic acids, proteins and starch be considered as step growth po...

    Text Solution

    |

  12. How is the following resin intermediate prepared and which polymer is ...

    Text Solution

    |

  13. To have practical applications why are cross links required in rubber?

    Text Solution

    |

  14. Why does cis-polyisoprene possess elastic property?

    Text Solution

    |

  15. What is the structural difference between HOP and LDP? How does the st...

    Text Solution

    |

  16. What is the role of benzoyl peroxide in addition polymerisation of alk...

    Text Solution

    |

  17. Which factor imparts crystalline nature to a polymer like nylon?

    Text Solution

    |

  18. Name the polymers used in laminated sheets and give the name of monome...

    Text Solution

    |

  19. Which type of biomolecules have some structural similarity with synthe...

    Text Solution

    |

  20. Why should the monomers used in addition polymerisation through free r...

    Text Solution

    |