The reaction ,` 2AB(g) + 2C(g) to A_(2(g)) + 2BC_((g))` proceeds according to the mechanism .
I. `2AB hArr A_(2)B_(2)` (fast)
II. `A_(2)B_(2)+C to A_(2)B + BC ` (slow )
III. `A_(2)B+C to A_(2)+BC` (fast)
what will be the initial rate taking [AB] = 0.2 M and [C] = 0.5 M ? The `K_(c)` for the step I is ` 10^(2) M^(-1)` and rate constant for the step II is ` 3.0 xx 10^(-3) mol^(-1) min^(-1)`

Options

A. `0.0716 M min^(-1)`
B. `0.0891 M min^(-1)`
C. `0.006 M min^(-1)`
D. `0.0257 M min^(-1)`

Answer

C