There were 800 litres, 725 litres and 575 litres kerosine oil in three kerosine oil drums in a house. The oil of these three drums is poured into a cuboidal pot and for this, the depth of oil in drums becomes 7 dcm. If the ratio of the length and breadth of the cuboidal pot is 4 : 3, then calculate the length and breadth of the pot. If the depth of the cuboidal pot· would be 5 dcm, calculate whether 1620 litre oil can be kept or not in that pot.

Explanation

The total quantity of oil in the three drums= (800 + 725 + 575) litres= 2100 litres = 2100 CU-'dcm.
Let the length of the cuboidal pot be 4x dcm and its breadth be 3x dcm. The depth of oil = 7 dcm. ` therefore` the volume o oil in the cuboinal pot `= 4x xx 3x xx 7 ` cu-dcm
As per question `4 x xx 3 x xx 7 =2100 or, x^2 = (2100)/(4xx 3xx7)` or ` x^2= 25 `or x=5
`therefore` the lenght of the pot `=4 xx 5` dcm = 20 dcm and breath of the pot `= 3 xx 5 ` dcm =15 dcm
Now, the volume of the cuboidal pot `= 20 xx 15 xx 5 ` cu-dcm = 1500 cu-dcm = 1500 dcm = 1500 litres
Hence if the depth of the cuboidal pot be 5 dcm, then 1620 litres oil can not be kept in that pot.