A soild cube is divided into two objects of equal volumes, then what will be the ratio of the total surface area of the cube and the surface area of each cuboidal object?

Explanation

Let the length of each side of the cube be a unit. Since the cube is divided into two cuboidal object, so the length of the vuboidal object will be a unit, breadth a unit and height `a/2` unit.
Now, the total surface area of the cube `=6a^2` sq-units and the total surface area fo each cboidal object
`=2(axxa+axxa/2+a/2xxa)`sq - units =2 `(a^2+a^2/2+a^2/2)` sq - units
`=2((2a^2+a^2+a^2)/(2))` sq - units = 2 `((4a^2)/(2))` sq- units `=4a^2`sq - units
So, (the total surface area of the cube ) : (the total surface area of each cuboidal object) `= 6a^2 : 4a^2` = 3 : 2
Hence the required ratio = 3 : 2.