Home
Class 10
MATHS
The base of an isosceles triangles is ...

The base of an isosceles triangles is 8.4 cm and the length of each of its equal sides is 9 cm. Construct this triangle and then by drawing its incricle , determine its inradius .(Givne construction signs only).

Text Solution

Verified by Experts

The correct Answer is:
2.5 cm
Promotional Banner

Topper's Solved these Questions

  • CONSTRUCTION OF CIRCUMCIRCLES AND INCIRCLE OF A TRIANGLE

    CALCUTTA BOOK HOUSE|Exercise EXERCISE- 7.1 ( MULTIPLE CHOICE QUESTION )|4 Videos

  • CONSTRUCTION OF CIRCUMCIRCLES AND INCIRCLE OF A TRIANGLE

    CALCUTTA BOOK HOUSE|Exercise EXERCISE - 7.1 ( FILL IN THE BLANKS )|2 Videos

  • CONCEPT OF MEASUREMENT OF ANGLES

    CALCUTTA BOOK HOUSE|Exercise EXERCISE - 1|38 Videos

  • CONSTRUCTION : DETERMINATION OF MEAN PROPORTIONAL

    CALCUTTA BOOK HOUSE|Exercise Exercise|20 Videos

Similar Questions

Explore conceptually related problems

The base of an isosceles triangle is 12 cm and the length of each of the equal sides is 10 cm, find the height of the triangle.

An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.

The perimeter of an isosceles triangle is 14 cm. The ratio of its lateral sides and base is 5:4 Then the area of the triangle is

The perimeter of an isoceles triangle is 544 cm. The length of each equal sides is (5)/(6) part of its base. Find the area of the triangle.

Draw an isosceles triangle having are 7.8 cm length of base and the length of each equal side of 6.5cm . Now draw the incircle of this triangle.