The arithmetic mean of 200 values of a variable is 50. Later on, it is found that two values 92 and 8 have been taken wrongly instead of 192 and 88 respectively . After correction , find the actual arithmetic mean of the given values.

Explanation

Here, the summation of the values of the variable `=underset(i=1)overset(200)sum x_(i)=200 barx`
`=200xx50=10000`
Taking correct values, the summation
`=10000-92-8+192+88=10180`
`therefore ` the corrected arithmetic mean `=(10180)/(200)=50.9`