In the window of a house, there is a ladder at an angle of `60^(@)` with the ground. If the ladder is `2sqrt(3)` m long, then calculate with figure, the height of the window above the ground.

Explanation

Let the height of the ground be AB. Then the right-angled triangle ABC, we get,
`sin60^(@)=(AB)/(AC)`[ by the definition of `sin theta`]
or, `(sqrt(3))/(2)=(AB)/(2sqrt(3)) or, AB=3`
Hence the window is 3 m high above the ground.