Home
Class 10
MATHS
In DeltaABC ray BD bisects angleABC " "A...

In `DeltaABC` ray BD bisects `angleABC " "A-D-C,"side DE || side BC"`
`A-E-B`
`"then prove",(AB)/(BC)=(AE)/(EB)`

Promotional Banner

Topper's Solved these Questions

  • SIMILARITY

    CHETAN PUBLICATION|Exercise Practice Set - 1.1|8 Videos
  • SIMILARITY

    CHETAN PUBLICATION|Exercise Practice Set - 1.2|13 Videos
  • QUADRATIC EQUATIONS

    CHETAN PUBLICATION|Exercise ASSIGNMENT|12 Videos
  • STANDARD IX SYLLABUS

    CHETAN PUBLICATION|Exercise PROBLEMS FOR PRACTICE|20 Videos

Similar Questions

Explore conceptually related problems

In DeltaABC, ray BD bisects angleABC,A-D-C, Side DE|| Side BC. A-E-B. then prove that AB:BC=AE:EB

In DeltaABC,"seg " BD" bisects "angleABC and"Ray " CE" bisects " angleACB. "if seg "AB~="seg "AC then prove that ED||BC.

In DeltaABC,"seg " BD" bisects "angleABC,"if" AB=x,BC=x+5,AD=x-2,DC=x+2 .Then find the value of x.

Bisector of angleB" and "angle C " in "DeltaABC meet each other at P. Line Ap cuts the side BC at Q. Then prove that : (AP)/(PQ)=(AB+BC)/(BC)

In a Delta ABC , AD is the bisector of angle A meeting side BC at D, if AB=10 cm, AC =14 cm and BC=6 cm, find BD and DC.

The internal bisector of angle A of Delta ABC meets BC at D and the external bisector of angle A meets BC produced at E. Prove that (BD)/(BE) = (CD)/(CE) .

In the adjoint figure, AD is the bisector of the exterior angleA" of "DeltaABC. Seg AD intersects the side BC produced in D. Prove that : (BD)/(CD)=(AB)/(AC)

D is the midpoint of the side BC of Delta ABC . If P and Q are points o AB and on AC such that DP bisects angle BDA and DQ bisects angle ADC , then prove that PQ || BC