Home
Class 10
MATHS
In the adjoining figure "seg "PSbot"ray ...

In the adjoining figure `"seg "PSbot"ray "RQ,"seg "QTbot"seg "PR. "If " RQ=6,PS=6andPR=12" then find "QT.`

Text Solution

Verified by Experts

The correct Answer is:
QT=3 units
Promotional Banner

Topper's Solved these Questions

  • SIMILARITY

    CHETAN PUBLICATION|Exercise Practice Set - 1.2|13 Videos

  • SIMILARITY

    CHETAN PUBLICATION|Exercise Practice Set - 1.3|9 Videos

  • SIMILARITY

    CHETAN PUBLICATION|Exercise ASSIGNMENT-1|12 Videos

  • QUADRATIC EQUATIONS

    CHETAN PUBLICATION|Exercise ASSIGNMENT|12 Videos

  • STANDARD IX SYLLABUS

    CHETAN PUBLICATION|Exercise PROBLEMS FOR PRACTICE|20 Videos

Similar Questions

Explore conceptually related problems

In the adjoining figure , "seg " BEbot"seg " ABand "seg " BAbot "seg " AD. If BE = 6, AD =9 , the find A(DeltaABE):A(DeltaBAD)

In the adjoining figure "seg " DHbot " seg " EF," seg " GKbot"seg " EF. If DH = 12 cm , GK =20 cm and A(DeltaDEF)=300^(@)"cm"^(2) , then find (i) EF (ii) A(DeltaGEF)

In the adjoining figure , "seg " PA , "seg " QB , "seg " , RC and "seg " SD " are" bot"to line " AB=6, BC=9,CD=12 and PS=36, then find PQ , QR and RS .

Solve the following sub question : in the adjoining figure, seg PS bat side QR. If PQ = a, PR = b QS = c and Rs = d then complete the following activity to prove that (a + b) (a - b) = (c + d) (c - d) Proof : In Delta PSQ angle PSQ = 90 ^(@) square^(2) = PS^(2) + square^(2) PS^(2) = square^(2) - square^(2) In Delta PSR, angle PSR = 90^(@) square^(2) = PS^(2) + square^(2) PS^(2) = square^(2) - square^(2) = square^(2) - square^(2) a^(2) - c^(2) = b^(2) - d^(2) a^(2) - b^(2) = C^(2) - d^(2) square xx square = square xx square

In the adjoining figure, angle PQR = 90^(@) "seg" QS bot side PR, PS = 4, PQ = 6. Find x,y and z.

In the adjoining figure , seg PQ || AB. Seg PR || seg BD. Prove that QR||AD.

In the adjoining figure , "seg " PQ||" seg " DE, A(DeltaPQF)=20 sq units . PF = 2 , then find A(squareDPQE) by completing the following activity.

In the adjoining figure "seg "Cebot" side " AB, " seg" AD bot" side " BC. Prove that (i) DeltaAEP~DeltaCDP (ii) DeltaAEP~DeltaADB

In the adjoining figure, angle QPR = 90^(@), "seg" PM bot hypotenuse QR, Q - M - R. If PM = 10, QM = 8 then find QR.

In the adjoining figure, if PQ = 6, QR = 10, PS = 8, then find TS.