D is a point on side BC of `DeltaABC` such that , `angleADC=angleBAC`. Show that `AC^(2)= BCxxDC` .

In the figure , in DeltaABC , point D on side BC is such that , DeltaBAC~=DeltaADC then prove that , CA^(2)-=CBxxCD .

In Delta ABC , AB = AC and BC = 6cm, D is a point on the side AC such that AD = 5cm and CD = 4cm, show that Delta BCD ~ Delta ABC and hence find DB .

In the figure, ABC is a triangle in which AB= AC. Points D and E are points on the side AB and AC respectively such that AD=AE. Show that points B, C, E and D lie on a same circle.

The perpendicular from A on side BC at a Delta ABC intersects BC at D such that DB=3 CD. Prove that 2 AB^(2)=2AC^(2)+BC^(2)

DeltaABC is an isosceles triangle in which AB = AC. Show that /_ B = /_ C.

Point D and E are the points on sides AB and AC such athat AB = 5.6 , AD = 1.4 , AC =7.2 and AE = 1.8 . Show that DE||BC.

D is the midpoint of the side BC of Delta ABC . If P and Q are points o AB and on AC such that DP bisects angle BDA and DQ bisects angle ADC , then prove that PQ || BC

In DeltaABC , seg DE|| side BC. If 2A (DeltaADE)=A(squareDBCE) . Show that BC=sqrt(3)xxDE .

In DeltaABC , P is a point on side BC such that BP = 4 cm and PC = 7 cm. A(DeltaAPC):A(DeltaABC) = ………………

If D is the midpoint of the side BC of a triangle ABC, prove that vec(AB)+vec(AC)=2vec(AD)