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sin theta.cosec theta = …….....

`sin theta.cosec theta` = ……..

A

1

B

0

C

`1/2`

D

`sqrt2`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If sin theta + cos theta theta = sqrt(2) cos theta then cos theta - sin theta is

    A
    `sqrt(2) cos theta`
    B
    `sqrt(2) sin theta `
    C
    `+- sqrt(2) sin theta `
    D
    `sqrt(2) ( cos theta + sin theta)`

  • the solution of sin ^3 theta cos theta - sin theta cos^3 theta = 1/4 is

    A
    `((n pi)/(4)) +(-1)^n ((pi)/(8))`
    B
    `((n pi )/(2)) +-( (pi)/(8))`
    C
    `((npi)/(4))+ (-1)^(n+1) ((pi)/(8))`
    D
    `((n pi)/(8))+(-1) ^n ((pi)/(8))`

  • The inverse of A=[[cos theta, sin theta],[-sin theta,cos theta]] is :

    A
    A
    B
    `-A`
    C
    `A^(T)`
    D
    `-A^(T)`

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