Suppose your are standing on a tall ladder. If your distance from the centre of the Eart is 2R, what will be your weight?

Explanation

Given: `R_(1)=2R`
To find: `W_(1)=?`
Formula: `W=F=(GMm)/(R^(2))`
Solutio: `W=(GMm)/(R^(2))`…………I
`W_(1)=(GMm)/((2R)^(2))`
`=(Gmm)/(4R^(2))`………..ii
`W_(1)=1/4xx[(GMm)/(R^(2))]`
`W_(1)=1/4W`…………[From (i)]
Weight will be one fourth the original weight.