Home
Class 10
PHYSICS
Let the period of revolution of a planet...

Let the period of revolution of a planet at a distance R from a star be T. Prove that if it was at a distance of 2R from the star, its period of revolution will be `sqrt(8)T`.

Text Solution

Verified by Experts

Given: Distance from sun `=R`
Time to Rotation `=T`
New distance `=2R`
To find: New time `T_(N)=?`
Formula: `(T^(2))/(R^(3))=k`
Solution: Case (i)
`(T^(2))/(R^(3))=k`…..i
Case (ii)
`(T_(N)^(2))=k` or `(T_(N)^(2))/(8R^(3))=k`............ii
From i and ii
`(T_(N)^(2))=(T^(2))/(R^(3))`
`T_(N)^(2)=8T^(2)`
`T_(N)=sqrt(8T^(2))`
`T_(N)=sqrt(8)T`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    CHETAN PUBLICATION|Exercise DEFINE/WRITE THE LAWS:|12 Videos
  • GRAVITATION

    CHETAN PUBLICATION|Exercise ANSWER THE FOLLOWING IS ONE OR TWO SENCTENCES:|7 Videos
  • GRAVITATION

    CHETAN PUBLICATION|Exercise SOLEVE THE FOLLOWING|6 Videos
  • DISASTER MANAGEMENT

    CHETAN PUBLICATION|Exercise ASSIGMENT-10|11 Videos
  • HEAT

    CHETAN PUBLICATION|Exercise ASSIGNMENT - 5 (Answer the following: (Any 1))|3 Videos

Similar Questions

Explore conceptually related problems

Accorrding to Kepler, the period of revolution of a planet (T) and its mean distance from the Sun ® related by the equation.

The period of revolution of planet A around the Sun is 8 times that of B. The distance of A from the Sun is how many times greater than that of B from the Sun.

The distance of planet Jupiter from the sun is 5.2 times that of the earth. Find the period of resolution of Jupiter around the sun.

Write down the moment of inertia of a disc of radius R and mass m about an axis in its plane at a distance R/2 from its centre.

The distances of two satellites from the surface of the Earth are 2R and 8R. Their time periods of rotation are in the ratio:

The distances of two satellites from the surface of the Earth are R and 7R. Their time periods of rotation are in the ratio:

Suppose that a satellite in space, an earth station and the centre of earth all lie in the same plane. Let r be the radius of earth and R be the distance from the centre of earth to the satellite. Let d be the distance from the earth station from the satellite. Let 30^(@) be the angle of elevation from the earth station to the satellite. if the line segment connecting earth station and satellite subtends angle alpha at the centre of earth, then prove that d =R sqrt(1 + ((r )/(R))^(2) - 2(r )/(R ) cos alpha) .

Prove that period of function f(x)=sinx, x in R " is " 2pi.

CHETAN PUBLICATION-GRAVITATION-NUMERICALS FOR PRACTICE
  1. A stone of mass 2 kg is falling from a certain height. Find the force ...

    Text Solution

    |

  2. The planet in space has mass twice as that of the Earth and a radius t...

    Text Solution

    |

  3. Calculate the value of g on the Moon, it its mass is 7.4xx10^(22)kg an...

    Text Solution

    |

  4. If the weight of a body on the surface of the Moon is 100N what is its...

    Text Solution

    |

  5. If the acceleration due to gravity on the surface of the Earth is 9.8m...

    Text Solution

    |

  6. Calculate the escape velocity on the surface of the Moon given the mas...

    Text Solution

    |

  7. Let the period of revolution of a planet at a distance R from a star b...

    Text Solution

    |

  8. The escape velocity for mass is 5.02km/s. If its radius is 3390 km, Wh...

    Text Solution

    |

  9. A planet orbits the Sun in time T at a distance of R from it. Another ...

    Text Solution

    |

  10. An object takes 5s to reach the ground from a height of 5m on a planet...

    Text Solution

    |

  11. A ball falls off a table and reaches the ground in 1s. Assuming g=10m/...

    Text Solution

    |

  12. An iron ball of mass of 3 kg is released from height of 125 m and fall...

    Text Solution

    |

  13. A tennis ball is thrown up and reaches a height of 4.05 m before comin...

    Text Solution

    |

  14. An object thrown vertically upwards reaches a height of 500m. What wa...

    Text Solution

    |

  15. Find a formula for maximum height attained by object.

    Text Solution

    |

  16. A stone thrown vertically upwards with initial velocity u reaches a he...

    Text Solution

    |

  17. A ball thrown up vertically returns to the person after 6s. Find the v...

    Text Solution

    |

  18. A boy drops a coin from the top of a building which is 49 m high. Find...

    Text Solution

    |

  19. A ball is thrown vertically upwards with velocity of 49 m/s. Calculate...

    Text Solution

    |

  20. A stone is thrown vertically upwards with initial velocity of 40 m/s. ...

    Text Solution

    |