A ball falls off a table and reaches the ground in 1s. Assuming `g=10m//s^(2)`, calculate its speed on reaching the ground and the height of the table.

Explanation

Given: Time `(t)=1s`
Gravitational acceleration `(g)=10m//s^(2)`
Initial velocity `(u)=0m//s`
To fid: Final velocity `(v)=?`
Displacement `(s)=?`
Formulae `v=u+"gt",s=ut+1/2"gt"^(2)`
Solution `:v=u+"gt"`
`=0+10xx1`
`v=10m//s`
`s=0+1/2xx10xx1^(2)`
`s=5m`
Speed on reaching ground is 10m//s and height of the table is 5m.