Balance the equation stepwise.
`Ag_((s)) + HCl_((aq))to AgCl darr +H_(2)uarr`

Explanation

Step 1: Write the chemical equation and count the numbers of atoms I reactants and products.
`Ag+ HCl to AgCl +H_(2)…………(1)`

Step 2: From the above table, we see the number of atoms of hydrongen on reactant side is not balanced. So hydrogen on reactant side is not balanced. So, to balance hydrogen atom, we write coefficient 2 for HCl.
`Ag +2HCl to Ag Cl+ H_(2)..............(2)`
Again count the number of atoms of elements on both sides.

Step 3: now to balance chlorine, we write coefficient 2 for AgCl
`Ag +2HCl to 2Ag Cl+ H_(2)............(3)`
Again count the number of atoms of elements on both sides.

Step 4: Atoms of elements, hydrogen and chlorine are now balanced. Number of atoms of Ag on product side is 2, and on reactant side is 1 to balacne number of atoms of Ag on reactant side, we write coefficient 2 for Ag.
`therefore 2Ag +2HCl to 2AgCl+H_(2)...........(4)`
Now count number of atoms is equation (4) again

In means equation (4) is a balanced equation.