Balance the equation stepwise.
`NaOH_((aq)) +H_(2)SO_(4(aq))to Na_(2) SO_(4(aq))+ H_(2)O _((l)).`

Explanation

Step 1: Write the equation given.
`NaOH +H_(2) SO_(4) to Na_(2)SO_(4) +H_(2)O " "…(1)`
Count the number of atoms of each element in products and reactants.

The number of oxygen and sulphur atoms are equal on both sids. Hence, we will balance Na atoms on both sides.
Step 2: To blaance Na atom we write coefficient 2 for naOH.
`2NaoH +H_(2) SO_(4) to Na_(2) SO_(4) +H_(2)O" "...(2)`
Step : 3 Count the number of Na atoms, H atoms, O atoms and S atoms on both sides.

Step 4: To balance H, we write coefficient 2 for `H_(2)o` on the product side. Hence the equation becomes.
`2NaOH +H_(2)SO_(4) to Na_(2) SO_(4) +2H_(2)O " "...(3)`
Again count the number of atoms of elements on both sides.

Now the number of atoms of elements are equal on both sides. hence, equation (3) is a balanced equation.