Balance the equation stepwise.
Write down the physical states of reactants and products in reactions.
`SO_(2) + 2H_(2) S to 3S +2H_(2)O`

Explanation

Step 1: Write the equation given.
`N_(2) +H_(2) to NH_(3)" "…(1)`
Now count the number of atoms of each elements on reactants and product side.
ltbgt Step 2: Number of atoms of elements on both side is not the same. So we need to balance it. First we will balance nitrogen by writing coefficient 2 for the product `NH_(3).`
`N_(2) +H_(2) to 2NH_(3)" "...(2)`
SDtep 3: Again count the number of atoms of elements on both sides.

Step 4: Number of atoms of Nitrogen is now balanced on both sides, but number of atoms of hydrogen is not balanced. Therefore we write coefficient 3 for Hydrogen on reactant side. The equation becomes :
`N_(2)+ 3H_(2) to 2NH_(3)" "...(3)`
Now, count the number of atoms on both side.

It means the equation (3) is a balanced equation.