Write the electrode reaction for electrolysis of molten Magnesium chloride and Calcium chloride.

Explanation

(i) For magnesium chloride
`Mg^(2+) + 2e^(-) to Mg` (magnesium metal at the cathode)
`2Cl^(-2)-2e^(-) to Cl_(2)` (chlorine gas at the anode.)
Magnesiu ions gain electrons (reductio) to form magnesium atoms. Chloride ions lose electrons (oxidation) to form chlorine atoms.
The overall reaction is
`MgCl_(2(l))to Mg_((g))+ Cl_(2(g)) uarr`
(ii) For Calcium chloride
`Ca^(2+)-2e^(-) to Ca` (calcium metal at the cathode)
`2Cl^(-)-2e^(-) to cl_(2)` (chlorine gas at the anode)
Calcium ions gain electrons (reduction) to form calcium atoms. Chloride ions lose electrons (oxidation) to form chlorine atoms.
Overall reaction is
`CaCl_(2) to Ca_((s))+Cl uarr`