In the `s-t` equations `(s=10+20t-5t^(2))` match the following

In the s-t equation (s=10+20 t-5t^(2)) match the following columns. |{:(,"Column I",,"Column II"),((A),"Distancec travelled in 3s",(p),-20" units"),((B),"Displacement 1 s",(q),15" units"),((C ),"Initial acceleration",(r ),25" units"),((D),"Velocity at 4 s",(s),-10" units"):}|

In the s-t equation (s=10+20 t-5t^(2)) match the following columns. |{:(,"Column I",,"Column II"),((A),"Distancec travelled in 3s",(p),-20" units"),((B),"Displacement 1 s",(q),15" units"),((C ),"Initial acceleration",(r ),25" units"),((D),"Velocity at 4 s",(s),-10" units"):}|

The displacement s of an object is given as a function of time t by the following equation s=2t+5t^(2)+3t^(3) . Calculate the instantaneous velocity of the object at t = 1 s.

The displacement s of an object is given as a function of time t by the following equation s=2t+5t^(2)+3t^(3) . Calculate the instantaneous velocity of the object at t = 1 s.

The maximum height is reached is 5s by a stone thrown vertically upwards and moving under the equation 10s=10ut-49t^(2) , where s is in metre and t is in second. The value of u is

Factorise: -5-10t + 20t ^(2)

A particle moves in the straight line as per the equation s = 2t^(3) - 6t^(2) + 20t ,where t is in seconds. when will the particles direction of acceleration change ?

A particle moves in the straight line as per the equation s = 2t^(3) - 6t^(2) + 20t ,where t is in seconds. when will the particles direction of acceleration change ?

The instantaneous angular position of a point on a rotating wheel is given by the equation theta(t) = 2t^(3) - 6 t^(2) The torque on the wheel becomes zero at a) t = 1 s b) t = 0.5 s c) t = 0.25 s d) t = 2 s