If `m!=n`where `m,n` are positive integers,then `int sin mx sin nxdx=`

int sin mx cos nxdx,m!=n

Integrate: int sin mx cos nxdx,m!=n

int cos mx cos nxdx,m!=n

Integrate: int cos mx cos nxdx,m!=n

Evaluate int cos mx cos nxdx where m,n are positive integers,m!=n What happens if m=n?

If m and n(n>m) are positive integers, then find the number of solutions of the equation n|sin x|=m|cos x| for x in[0,2 pi] Also find the solution.

If m and n are positive integers and m!=n show (i) int_(0)^(2 pi)sin mx sin nxdx=0 (ii) int_(0)^( pi)cos mx cos nxdx=0 (iii) int_(0)^( pi)cos^(m)x

Evaluate int cosmx cosnx dx , where m,n are positive integers and m ne n . What happens if m=n?

If (m)=64, where m and n are positive integers,find the value of n)^(mn)..