134 xta x+20 x+3al +2 +3 x + 40 = 0. x +49 x + 5a x+6al 4. fa x

In the figure, sed LM || side BC, AL = x + 3, BL = x - 3, AM = x + 5 and CM = x - 2 then complete the following activity to find the value of x. Activity : In Delta ABC , sed LM || side BC, :. by ________ theorem, (AL)/(LB) = (AM)/(square) :. (x + 3)/(x - 3) = (x + 5)/(square) :. (x + 3) ________ =(x + 5) (x - 3) x^(2) + x - square = x^(2) + 2x - 15 :. x = square

If the roots of x^4 +5x^3 - 30 x^2 - 40 x+64=0 are in G.P then roots of x^4 - 5 x^3 - 30 x^2 + 40 x+ 64 =0 are in

If the roots of x^4 +5x^3 - 30 x^2 - 40 x+64=0 are in G.P then roots of x^4 - 5 x^3 - 30 x^2 + 40 x+ 64 =0 are in

If the roots of x^(4) + 5x^(3) - 30x^(2) - 40x + 64 = 0 are in G.P. then the roots are

x^2-2x+2=0"( 2)"x^2-3x+3=0x^2-3x+4=0"( 4)"x^2-5x+5=0 A quadratic equation whose roots are cosec20 andsec 0 can be(1) x2-2x+ 2 =0(2) x2-3x + 3 = 0(3) x2-3x+ 4= 0(4) x-5x+5= 0

The perimeter of a triangle is 20 and the points (-2, -3) and (-2,3) are two of the vertices of it. Then the locus of third vertex is : (x-2), y = 49 40 (x+2) y? = 1 49 40 (x+2)? y? 1 40 49 (x-2) y = 40 49