Find the value of `int_0^(2pi) |sinx|dx`

Write the value of int_0^(pi//2) (sinx) dx - int_0^(-pi//2) (cos x) dx

Evaluate int_(0)^(2pi)|sinx|dx .

Find the value of int_0^(pi/2) cosx/(1+sinx)^2dx

Find the value of int_0^(pi/2) cosx/(1+sinx)^2dx

The value of int_(0)^(2pi)|cosx-sinx|dx is equal to

Evaluate: int_0^(2pi) [2sinx]dx

Evaluate int_0^(pi//2) log|sinx| dx

Evaluate int_(0)^(pi) sinx dx

Evaluate : int_0^(pi/2) x sinx dx

(i) Show that int_(0)^(pi)xf(sinx)dx =(pi)/(2)int_(0)^(pi)f (sin x)dx. (ii) Find the value of int_(-1)^(3//2)|x sin pix|dx .