" 17.xylog "(x+y)=1

Find (dy)/(dx) , when: xylog(x+y)=1

(dy)/(dx)=(xy)/((1-x)(1+y)) A) x+y+log[y(1-x)]=c B) x+y+log[x(1-y)]=c C) x+y+log(x+y)=c D) y-x+log[x(1-y)]=c

The solution of xy.log((x)/(y))dx+{y^(2)-x^(2)log((x)/(y))}dy =

If frac(xylog(xy))(x+y)=frac(yzlog(yz))(y+z)=frac(zxlog(zx))(z+x) then show that x^x=y^y=z^z

Show that the differential equation xylog(y/x)dx+{y^(2)-x^(2)log(y/x)}dy=0 is homogeneous and solve it.

Fill ups The differential equation (dx)/(dy)=(x^2log(x//y)-x^2)/(xylog(x/y)) can be solved by the substitution……………

If x^y+y^x= (x+y)^(x+y) , then prove that dy/dx= ((x+y)^(x+y) [1+log(x+y)]-yx^(y-1)-y^xlogy)/(x^ylogx+xy^(x-1) -(x+y)^(x+y) [1+log(x+y)]