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The vertices of a triangle are A(1,1,2),...

The vertices of a triangle are A(1,1,2), B (4,3,1) and C (2,3,5). The vector representing internal bisector of the angle A is

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Let AD is the bisector of `/_A`.Then,
`(BD)/(DC) = (AB)/(AC)`eq(1)
Given the vertices of triangle,
`AB = sqrt(3^2+2^2+1^2) = sqrt(14)`
`AC = sqrt(1^2+2^2+3^2) = sqrt(14)`
As AB = BC, So, BD = DC(from eq(1))
It means D is middle point of BC. So, vertices of D will be (3,3,3).
So, vector AD will be `2hati+2hatj+hatk`.
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