The circumference of the second Bohr orbit of electron in hydrogen atom is `600nm` . The potential difference that must be applied between the plates so that the electron have the de Broglie wavelength corresponding in this circumference is

The circumference of the second Bohr orbit of electron in the hydrogen atom is 600nm. Calculate the potential difference to which the electron has to be subjected so that the electron stops. The electron had the de Broglie wavelength corresponding to the circumference.

The circumference of the second Bohr orbit of an electron in a hydrogen atom is 600 nm Calculate the potential difference to which the electron has to be Broglie wavelength curresponding to this circumferance

The de Broglie wavelength of an electron in the first Bohr orbit is

The de-Broglie wavelength of an electron in the first Bohr orbit is

The de-Broglie wavelength of an electron in the first Bohr orbit is

The de Broglie wavelength of an electron in the 3rd Bohr orbit is

The circumference of first orbit of hydrogen atom is .S.. Then the Broglie wavelength of electron in that orbit is

The radius of the second orbit of an electron in hydrogen atom is 2.116A . The de Broglie wavelength associated with this electron in this orbit would be