Two springs, of spring constants `k_(1)` and `K_(2)`, have equal highest velocities, when executing SHM. Then, the ratio of their amplitudes (given their masses are in the ratio `1:2`) will be

Options

A. `k_(1)//k_(2)`
B. `(k_(1)//k_(2))^(1//2)`
C. `k_(2)//k_(1)`
D. `(k_(2)//k_(1))^(1//2)`

Answer

B

Explanation

Kinetic energies of both the masses are equal.
So, ` (1)/(2)k_(1)A_(1)^(2)= (1)/(2)k_(2)A_(2)^(2) " or " (A_(1))/(A_(2)) = sqrt((k_(2))/(k_(1)))`