In Fig . 7.151 , coefficient of kinetic friction between the 4 kg block and the inclined surface is `(1)/(sqrt3)` . Here 'm' is such a mass that the 4 kg block is moving up the plane with a constant speed , then m is :

If the coefficient of friction between M and the inclined surfaces is mu = 1//sqrt(3) find the minimum mass m of the rod so that the of mass M = 10 kg remain stationary on the inclined plane

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

In Fig. 6-49, two blocks are connected over a pulley. The mass of block A is 15 kg, and the coefficient of kinetic friction between A and the incline is 0.20 Angle theta of the incline is 30^(@) . Block A slides down the incline at constant speed. What is the mass of block B?

An ice cube is kept on an inclined plane of angle 30^(@) . The coefficient to kinetic friction between the block and incline plane is 1//sqrt(3) . What is the acceleration of the block ?

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

In the figure show below, calculate the coefficient of friction between the block and the inclined plane. Assume that the mass of the block s 1 kg. The block is released from rest and stops by covering the distance of 0.1 m on the plane.