A particle is projected horizontally from a tower with velocity u towards east. Wind provides constant horizontal acceleration `(g)/(2)` towards west. If particle strikes the ground vertically the then :

A particle is projected horizontally from a tower with velocity V_(0) . Wind is blowing in opposite direction and is providing a constant horizontal acceleration a_(0) . If particle strikes the ground vertically then height of building is

A particle Is projected at point 'A' with initial velocity 5 m//s at an angle theta = 37^(@) with the vertical y axis. A strong horizontal wind gives the particle a constant horizontal acceleration 6 m//s^(2) in the x direction. If the particle strikes the ground at a point directly under its released position, determine the height 'h' of point A . The downward acceleration is taken as the constant g = 10 m//s^(2) (take sin37^(@) = (3)/(5), cos37^(@) = (4)/(5) )

A particle Is projected at point 'A' with initial velocity 5 m//s at an angle theta = 37^(@) with the vertical y axis. A strong horizontal wind gives the particle a constant horizontal acceleration 6 m//s^(2) in the x direction. If the particle strikes the ground at a point directly under its released position, determine the height 'h' of point A . The downward acceleration is taken as the constant g = 10 m//s^(2) (take sin37^(@) = (3)/(5), cos37^(@) = (4)/(5) )

A particle is projected form ground with velocity u ar angle theta from horizontal. Match the following two columns.