If we reduce `3x+3y+7=0` to the form `xcosalpha+ysinalpha=p ,` then find the value of `pdot`

If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then find the value of p

If we reduce 3x+3y+7=0 to the form xcosalpha+ysinalpha=p , then the value of p is 7/(2sqrt(3)) (b) 7/3 (c) (3sqrt(7))/2 (d) 7/(3sqrt(2))

If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then the value of p is (7)/(2sqrt(3))( b) (7)/(3)( c) (3sqrt(7))/(2)( d) (7)/(3sqrt(2))

Reduce the equation x+sqrt3y-4=0 to the normal form x cos alpha+y sin alpha=p , and hence find the values of alpha and p .

Find the area of the triangle formed by the straight line xcosalpha+ysinalpha=p with the axes of coordinates.

Reduce x+sqrt(3y) + 4 = 0 to the : (iii) Normal form and find the values of p and alpha

Reduce x+sqrt(3y) + 4 = 0 to the : (iii) Normal form and find the values of p and alpha

Reduce x+sqrt(3y) + 4 = 0 to the : (iii) Normal form and find the values of p and alpha

Reduce x+sqrt(3y) - 4 = 0 to the : (iii) Normal form and find the values of p and alpha

Show that the circle on the chord xcosalpha+ ysinalpha-p = 0 of the circle x^2+ y^2 = a^2 as diameter is x^2 + y^2 - a^2 - 2p (xcosalpha + ysinalpha-p) = 0.