The number of molecules in 100 mL of `0.02N` `H_(2)SO_(4)` is:

Options

A. (a)`6.02xx10^(20)`
B. (b)`6.02xx10^(18)`
C. (c )`6.02xx10^(21)`
D. (d)`6.02xx10^(22)`

Answer

A

Explanation

`m_("eq")=NV_(mL)="n-factor"xxmm`
`:. Mm=0.02/2` or moles`=(0.02xx100)/(2xx1000)`
or Number of `H_(2)SO_(4)" molecules"=(0.02xx100)/(2xx1000)xx6.02xx10^(23)`
`=6.02xx10^(20)`