`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

Options

A. (a)0.1 M
B. (b)0.01 M
C. (c )0.02 M
D. (d)0.001 M

Answer

B

Explanation

`M=("Moles of urea")/("V in litre")`
`=(6.02xx10^(20)xx1000)/(6.023xx10^(23)xx100)=10^(-2) M`