Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:

Options

A. (a)0.44 mol `kg^(-1)`
B. (b)1.14 mol `k^(-1)`
C. (c )3.28 mol `kg^(-1)`
D. (d)2.28 mol `kg^(-1)`

Answer

D

Explanation

weight of acetic acid=`2.05xx60=123 g`
Weight of solution`=1000xx1.02=1020 g`
`:.` Weight of water`=(1020-123)=897 g`
`:.` Molality`=(2.05xx1000)/897=2.285`