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One litre hard water contains 12.00 mg M...

One litre hard water contains 12.00 mg `Mg^(2+)` millieqivalent of washing soda required to remove its hardness is

A

(a)1

B

(b)12.15

C

(c )`1xx10^(-3)`

D

(d)`12.5xx10^(-3)`

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The correct Answer is:
To solve the problem of determining the milliequivalent of washing soda required to remove the hardness from 1 litre of hard water containing 12.00 mg of \( Mg^{2+} \), we can follow these steps: ### Step 1: Understand the Concept of Milliequivalents Milliequivalents (mEq) are a measure of the reactive capacity of a substance. For ions, it is calculated based on the charge of the ion and its molar mass. ### Step 2: Calculate the Milliequivalents of \( Mg^{2+} \) We need to calculate the milliequivalents of \( Mg^{2+} \) present in the hard water. The formula for milliequivalents is: \[ \text{Milliequivalents} = \frac{\text{Weight (g)}}{\text{Equivalent Weight (g/equiv)}} \times 1000 \] ### Step 3: Determine the Equivalent Weight of \( Mg^{2+} \) The equivalent weight of an ion can be calculated using the formula: \[ \text{Equivalent Weight} = \frac{\text{Molar Mass}}{\text{Valency}} \] For \( Mg^{2+} \): - Molar Mass of \( Mg \) = 24 g/mol - Valency of \( Mg^{2+} \) = 2 Thus, the equivalent weight of \( Mg^{2+} \) is: \[ \text{Equivalent Weight of } Mg^{2+} = \frac{24 \, \text{g/mol}}{2} = 12 \, \text{g/equiv} \] ### Step 4: Substitute Values into the Milliequivalent Formula Now, substituting the values into the milliequivalent formula for \( Mg^{2+} \): \[ \text{Milliequivalents of } Mg^{2+} = \frac{12 \times 10^{-3} \, \text{g}}{12 \, \text{g/equiv}} \times 1000 \] ### Step 5: Calculate the Result Performing the calculation: \[ \text{Milliequivalents of } Mg^{2+} = \frac{12 \times 10^{-3}}{12} \times 1000 = 1 \, \text{mEq} \] ### Step 6: Conclusion Since the milliequivalents of washing soda required to remove the hardness is equal to the milliequivalents of \( Mg^{2+} \), we conclude that: \[ \text{Milliequivalents of washing soda required} = 1 \, \text{mEq} \] Thus, the answer is **1 milliequivalent**. ---

To solve the problem of determining the milliequivalent of washing soda required to remove the hardness from 1 litre of hard water containing 12.00 mg of \( Mg^{2+} \), we can follow these steps: ### Step 1: Understand the Concept of Milliequivalents Milliequivalents (mEq) are a measure of the reactive capacity of a substance. For ions, it is calculated based on the charge of the ion and its molar mass. ### Step 2: Calculate the Milliequivalents of \( Mg^{2+} \) We need to calculate the milliequivalents of \( Mg^{2+} \) present in the hard water. The formula for milliequivalents is: ...
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