In Haber process 30 litre of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only`50%` of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end ?

Options

A. (a)20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
B. (b)20 litres ammonia, 20 litres nitrogen, 20 litres hydrogen
C. (c )10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
D. (d)20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen

Answer

C

Explanation

`underset((1 vol.),(10 litre))(N_(2))+underset((3 vol.),(30 litre))(3H_(2)) rarr underset((2 vol.),(20 litre))(2NH_(3))`
It is given that only 50 % of the expected product is formed hence only 10 liters of `NH_(3)` is formed
`N_(2) "used" =5 " litres", "left" =30-5=25` litres
`H_(2)` used=15 litres, left`=30-15` litres