If the density of water is 1 g `cm^(-3)` then the volume occupied by one molecule of water is approximately

Options

A. (a)`6.023xx10^(-3) cm^(3)`
B. (b)`3.0xx10^(-3) cm^(3)`
C. (c )`5.5xx10^(-23) cm^(3)`
D. (d)`9.0xx10^(-23) cm^(3)`

Answer

B

Explanation

`1000 g H_(2)O=1000 cm^(3) H_(2)O`
`1000/18 "mole" H_(2)O=1000 cm^(3) H_(2)O`
`1000/18xx6.023xx10^(23)` molecule of `H_(2)O`
`=1000 cm^(3) H_(2)O`
`implies ` Volume of `1 "molecule"=1000/1000xx18/(6.023xx10^(23))`
`=3.0xx10^(-23) cm^(3)`.