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How many grams of concentrated nitric ac...

How many grams of concentrated nitric acid solution should be used to prepare `250 mL` of `2.0 M HNO_(3)`? The concentrated acid is `70% HNO_(3)`:

A

(a)`90.0` g conc. `HNO_(3)`

B

(b)`70.0` g conc. `HNO_(3)`

C

(c )`54.0` g conc. `HNO_(3)`

D

(d)`45.0` g conc. `HNO_(3)`

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To solve the problem of how many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO₃, we can follow these steps: ### Step 1: Calculate the number of moles of HNO₃ needed The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. We can use the formula: \[ \text{Number of moles} = \text{Molarity} \times \text{Volume (in liters)} \] Given: - Molarity = 2.0 M - Volume = 250 mL = 0.250 L Calculating the number of moles: \[ \text{Number of moles} = 2.0 \, \text{mol/L} \times 0.250 \, \text{L} = 0.5 \, \text{moles} \] ### Step 2: Calculate the mass of HNO₃ required Next, we need to find the mass of HNO₃ required using its molar mass. The molar mass of HNO₃ can be calculated as follows: - Atomic weight of H = 1 g/mol - Atomic weight of N = 14 g/mol - Atomic weight of O = 16 g/mol (and there are 3 oxygen atoms) Calculating the molar mass: \[ \text{Molar mass of HNO₃} = 1 + 14 + (3 \times 16) = 63 \, \text{g/mol} \] Now, we can calculate the mass of HNO₃ required: \[ \text{Mass of HNO₃} = \text{Number of moles} \times \text{Molar mass} = 0.5 \, \text{moles} \times 63 \, \text{g/mol} = 31.5 \, \text{grams} \] ### Step 3: Calculate the mass of concentrated nitric acid solution needed Since the concentrated nitric acid solution is 70% HNO₃, we need to find out how much of the concentrated solution is required to obtain 31.5 grams of HNO₃. Let \( x \) be the mass of the concentrated solution needed. Since 70% of this mass is HNO₃, we can set up the equation: \[ 0.70x = 31.5 \, \text{grams} \] Solving for \( x \): \[ x = \frac{31.5}{0.70} = 45 \, \text{grams} \] ### Conclusion To prepare 250 mL of 2.0 M HNO₃, you will need **45 grams** of concentrated nitric acid solution. ---

To solve the problem of how many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO₃, we can follow these steps: ### Step 1: Calculate the number of moles of HNO₃ needed The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. We can use the formula: \[ \text{Number of moles} = \text{Molarity} \times \text{Volume (in liters)} \] ...
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