Equal masses of `H_(2)`, `O_(2)` and methane have been taken in a container of volume `V` at temperature `27^(@)C` in identical conditions. The ratio of the volume of gases `H_(2) : O_(2)` : methane would be

Options

A. (a)`8:16:1`
B. (b)`16:8:1`
C. (c )`16:1:2`
D. (d)`8:1:2`

Answer

c

Explanation

According to Avogadro's hypothesis,
Volume of a gas `(V) prop` number of moles (n)
Therefore, the ratio of the volumes of gases can be determined in terms of their moles.
The ratio of volume of `H_(2):O_(2)`: methane `(CH_(4))` is given by
`V_(H_(2)):V_(O_(2)):V_(CH_(4))=n_(H_(2)):n_(O_(2)):n_(CH_(4))`
`implies V_(H_(2)):V_(O_(2)):V_(CH_(2))=m_(H_(2))/M_(H_(2)):m_(O_(2))/M_(O_(2)):m_(CH_(4))/M_(CH_(4))`
But `m_(H_(2))=m_(O_(2))=m_(CH_(4))=m [ :' n=("mass")/("molar mass")]`
Thus, `V_(H_(2)):V_(O_(2)):V_(CH_(4))=m/2:m/32:m/16=16:1:2`