Calculate the number of oxalic acid molecules in `100` mL of `0.02` N oxalic acid

Options

A. `6.023xx10^(20)`
B. `6.023xx10^(21)`
C. `6.023xx10^(22)`
D. `6.023xx10^(23)`

Answer

A

Explanation

Normality = Molarity`xx` Valence factor
`:.` Molarity`="Narmality"/("Valence factor")`
Valence factor for oxalic acid
`=("mo. Wt. of oxalic acid")/("Eq. wt. of oxalic acid")`
`=("mo. Wt. of oxalic acid")/("mo. Wt. of oxalic acid")xx 2`
(As basically of oxalic acid is)
`"Molarity"=20/2=0.01`
Number of millimoles `=0.01xx100`
Number of moles=`0.001`
`:.` Number of oxalic acid molecules`=0.001xx6.023xx10^(23) = 6.023xx10^(20)`