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1.82 g of a metal required 32.5 mL of N-...

1.82 g of a metal required 32.5 mL of N-HCl to dissolve it what is the equivalent weight of metal?

A

(a)54

B

(b)56

C

(c )28

D

(d)86

Text Solution

Verified by Experts

The correct Answer is:
b
Meq. Of metal =Meq. Of `HCl`
`1.82/E_(M)xx1000=32.5xx1`
`:. E_(M)=56`
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