How many grams of NaHSO(3) will be requi...

How many grams of `NaHSO_(3)` will be required to react with one litre of `NaIO_(3)` solution containing 5.8 g `NaIO_(3)` according to the reaction?

(a)10.2 g

(b)9.8 g

(c )9.14 g

(d)8.2 g

Text Solution

Verified by Experts

The correct Answer is:

Meq. Of `NaHSO_(3)`=Meq. of `NaIO_(3)`
`=NxxV=5.8/198xx6xx1000 ("n-factor for" NaIO_(3)=6) =175.76`
`W_(NaHSO_(3))/M_(NaHSO_(3))xx2xx1000=175.76`
`W_(NaHSO_(3))=(175.76xx104)/2000=9.14 g`

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