A `5.0 mL` of solution of `H_(2)O_(2)` liberates `0.508 g` of iodine from acidified `KI` solution. Calculate the strength of `H_(2)O_(2)` solution in terms of volume strength at `STP`.

Options

A. (a)2.2%
B. (b)3.8%
C. (c )4.48%
D. (d)None of these

Answer

c

Explanation

Meq. of `H_(2)O_(2)` =Meq. of `I_(2)`
`implies W_(H_(2)O_(2))/34xx2xx1000=0.508/254xx2xx1000`
`:. W_(H_(2)O_(2))=0.06 g`
`H_(2)O_(2) rarr H_(2)O_(2)+1/2 O_(2)`
`:' 34 g H_(2)O_(2)` gives 11.2 litres of `O_(2)` at STP
`:. 0.068` g gives`=11.2/34xx0.068=22.4 ml O_(2)`
`:.` Volume Stength of `H_(2)O_(2)=22.4/5=4.48` volume