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A 0.1097 g sample of As(2)O(3) requried ...

A `0.1097 g` sample of `As_(2)O_(3)` requried `26.10 mL` of `KMnO_(4)` solution for its titration. The molarity of `KMnO_(4)` solution is
molarity `=0.017 M~~0.018`

A

(a)0.02

B

(b)0.04

C

(c )0.018

D

(d)0.3

Text Solution

Verified by Experts

The correct Answer is:
c

Let molarity of `KMnO_(4)` solution be `M`
`:.` Eq. of `As_(2)O_(3)`=Eq. of `KMnO_(4)` solution
`0.1097/198xx4=(26.10xxMxx5)/1000`
`("Equivalent weight" As_(2)O_(3)=198/4)`
`molarity =0.017 M~~ 0.018`
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