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The ratio of energy of photon of lambda ...

The ratio of energy of photon of `lambda = 2000 Å` to that of `lambda = 4000 Å` is

A

`.^1//_(4)`

B

4

C

`.^1//_(2)`

D

2

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `E = (hc)/(lamda) , lamda_1 = 2000 Å , 12 = 4000 Å ,`
so `(E_1)/(E_2) = (lamda_2)/(lamda_1) = (4000)/(2000) = 2`.
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