The wavelength of the radiations emitted when in a hydrogen atom electron falls from infinity to stationary state is ` : (R_H = 1. 097 xx10^7 m^(-1))` .

Options

A. `9.1 xx 10^-8 nm`
B. 192 m
C. 406 nm
D. 91 nm

Answer

D

Explanation

(d) `(1)/(lamda) = R_H[(1)/(oo) -(1)/(l^2)]`
:. `lamda =(1)/(R_H) = (1)/(1.097 xx 10^7) m = 9.1 xx 10^-8 m`
=`91 xx 10^s m = 91 nm`.