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The angular momentum of d electron is...

The angular momentum of d electron is

A

`sqrt(6) (h//2 pi)`

B

`sqrt(2) (h//2 pi)`

C

`(h//2 pi)`

D

`2(h//2 pi)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) The expression for orbital angular momentum is
Angular momentum `= sqrt(l(l + 1)) ((h)/(2 pi))`
For `d`orbital, `1 = 2`
Hence, `l = sqrt(2(2+1)) ((h)/(2pi)) = sqrt(6) ((h)/(2 pi))`.
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