The correct set of four quantum number for the valence (outermost) electron of radiation `(Z = 37)` is

Options

A. `5, 0, 0, + (1)/(2)`
B. `5, 1 , 0, + (1)/(2)`
C. `5, 1, 1, + (1)/(2)`
D. `6, 0, 0, + (1)/(2)`

Answer

A

Explanation

(a) Electronic configuration of `Rb_((37))` is
`1 s^2 2 s^2 2 p^6 3 s^3 3 p_3^(6)3 d^10 4 s^2 4 p^6 5 s^1`
So for the valence shell electron `(5 s^1)`
`n = 5, l = 0, m = 0, s = + (1)/(2)`.