The number of electrons having `l = 0` chlorine atom `(Z = 17)` is

Options

A. 2
B. 4
C. 6
D. 5

Explanation

To determine the number of electrons with \( l = 0 \) in a chlorine atom (with atomic number \( Z = 17 \)), we can follow these steps:

### Step 1: Identify the Atomic Number
The atomic number of chlorine is \( Z = 17 \). This means that a chlorine atom has 17 electrons.

### Step 2: Write the Electronic Configuration
The electronic configuration of chlorine can be determined by filling the orbitals according to the Aufbau principle. The configuration is as follows:
- 1s²
- 2s²
- 2p⁶
- 3s²
- 3p⁵

So, the complete electronic configuration of chlorine is:
\[ \text{1s}^2 \, \text{2s}^2 \, \text{2p}^6 \, \text{3s}^2 \, \text{3p}^5 \]

### Step 3: Identify the Subshells
In quantum mechanics, the azimuthal quantum number \( l \) defines the shape of the orbital:
- \( l = 0 \) corresponds to the s subshell.
- \( l = 1 \) corresponds to the p subshell.

### Step 4: Count the Electrons in the \( l = 0 \) Subshell
From the electronic configuration:
- The 1s subshell has \( 2 \) electrons (1s²).
- The 2s subshell has \( 2 \) electrons (2s²).
- The 3s subshell has \( 2 \) electrons (3s²).

Now, we sum up the electrons in the s subshells:
- Total electrons with \( l = 0 \) (s subshells) = \( 2 + 2 + 2 = 6 \).

### Final Answer
The number of electrons having \( l = 0 \) in a chlorine atom is **6**.

---