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The orbital angular momentum of an elect...

The orbital angular momentum of an electron in`2s`orbital is

A

`+ (1)/(2) (h)/(2 pi)`

B

zero

C

`(h)/(2pi)`

D

`sqrt(2) (h)/(2 pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) Orbital angular momentum `= sqrt(l(l + 1)) (h)/(2 pi) = 0` (since `l = 0` for s orbital).
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